columns. The datediff function returns the difference between two specified dates in the time units that you specify: years, quarters, months, weeks, days, hours, minutes, or seconds. One option that avoids needing to add EndDate + 23:59:59. It creates it using the year in cell E17, and the month in cell E17. datediff isn't a function in Oracle. In Oracle, MONTHS_BETWEEN(date1, date2) function returns the number of months between two dates as a decimal number. DATEADD ('week', 1, [due date]) Add 280 days to the date February 20, 2021. If you omit it, the ROUND () function. from this previous question How to calculate age in T-SQL with years, months, and days you can do procedure like this. Improve this answer. DATEDIFF(datepart, startdate, enddate) Parameters. In SQL Server, there is a function datediff with datepart 'q'/quarter which behaves as follows :--. 365 / 365. I have a table where PurchasedDate is maintained. In effect, substr (to_date ('01-02-2018','mm-dd-yyyy'),4,3) is the same as. DateDiff ( date1, date2, date_part) パラメータ 説明; date1. I am trying to come up with a way in Oracle to calculate the difference between dates in days. Teams. g. Tip 032: Summary of Date Functions. Also, according to Oracle's documentation LAST_DAY returns a DATE. February 28 and March 31) can lead to unintuitive behavior; specifically, increasing the first date in the pair does not always increase the output value. The format argument is optional. ) and the. The minus sign is used to compute the difference between two. Aug 17, 2021 at 11:13. To answer your question to find all records that occurred last month. SHOW_DAY is an alias to store the day. Modified 3 years, 2 months ago. What I am using is (Today-Dob)/30/12, but this is not accurate as some months have 31 days. DATEDIFF. DECLARE @yourDate DATE = '20160229' select DATEADD (MONTH, DATEDIFF (MONTH, -1, @yourDate)-1, -1) Just a note: this does remove any time portion in the input date, which may or may not be desired. This function adds a number (a signed integer) to a datepart of an input date, and returns a modified date/time value. DateGroup. select (dt1-dt2) * 24 * 60 * 60 from t; dt1-dt2 gives diff in days (eg: 1. You may: count the number of 24h elapsed time: day+1 - day = 1 day = 24h. If I run. The MONTHS_BETWEEN () function is used to get the number of months between dates (date1, date2). MONTHS_BETWEEN (TO_DATE ('2003/01/01', 'yyyy/mm/dd'), TO_DATE ('2003/03/14', 'yyyy/mm/dd') ) would return -2. DATEDIFF_BIG () is a SQL function that was introduced in SQL Server 2016. We would like to show you a description here but the site won’t allow us. It means that the DATEPART function returns the number of times the boundary between two units is crossed. date. You should consider how many. to get the date one second before midnight of. Because the months are 06 in both dates. You could also use the add_months function: AND s. Factor by 24 to get hours, 24*60 to get minutes, 24*60*60 to get seconds (that's as small as dates go). DATEDIFF(MONTH, 0, GETDATE())-1, 0) AND DATEADD(MONTH, DATEDIFF(MONTH, -1, GETDATE())-1, -1) based on the comment below I have modified the query. The following illustrates the syntax of the DATEPART. What's the function in Oracle that would be the equivalent to DATEDIFF in the SQL Server? On Oracle, it is an arithmetic issue: Select DATE1. * FROM #HRAL h INNER JOIN #LAZY_DATE_DIM dd ON dd. It is the unit in which the DATEDIFF() function returns the difference between a start date and an end date e. (Oct 2006 - June 2005 = 16) DP_WEEK returns the distance between the weeks capturing the input dates. Because the precision is 3, the fractional second ‘6789’ is rounded to ‘679’. ROUND(p1) ROUND(p1, p2) Not Available. DATE_ADD. i. 0. user637544 Jun 1 2009 — edited Jun 1 2009. MONTH, YEAR, WEEK, etc are not allowed for. COMPUTE days3 = CTIME. Oracle GoldenGate add trandata errors. DP_MONTH returns the distance between the months capturing the input dates. months_between/120 = decades_between. It can be used to do date math as well. Parameter Description; interval: Required. This function is used to get the timestamp value from the specified character string. StandardDeviationSample(group. CancelDate IS NOT NULL THEN (CONVERT(NVARCHAR(MAX), DATEDIFF(day, Trips. It works according to the Gregorian Calendar. Would give you rows where date2 (the later date) is 60 to 90 days later than date1. date_from, evnt. If date1 is later than date2 , then the result is positive. SS: 差異を秒数で計算します。. 0. Apr 5, 2021 at 15:55. In Oracle, MONTHS_BETWEEN(date1, date2) function returns the number of months between two dates as a decimal number. As per the methodology used in this date calculator, a week starts on 'Monday' and ends on 'Sunday'. @Mohit224 - If you are saying that you want to ignore any fractional part of a year, then you. (Query using SQL server 2005 and 2008 is allowed). for extended XSL functions. Just to make the warning explicit to everyone looking at this answer: the subquery SELECT ROW_NUMBER() OVER ( ORDER BY c. I want to find out the customers who have made orders on three successive months. lastModified - w. This post has been answered by 630199 on Jun 1 2009. Current Date/Time. g. SELECT DATE '0016-08-03' - DATE '2016-07-08' FROM dual;-- -730461. So in order to get specific type of delivery for the last 3 months I was thinking to get today's date and convert it to 01/mm/yyyy format and ref it with the delivery month in the table to get least 3 month including. SELECT * FROM TABLE_NAME WHERE DATEADD (DAY, -90, GETDATE ()) between txtFromDate and txtToDate. I say ALL months as months can have 28 days (29 in a leap year), 30 days and 31 days which is why I wouldn't simply calculate the days between two dates. CREATE OR REPLACE FUNCTION dateDiff ( p_dt1 IN DATE, p_dt2 IN DATE ) RETURN NUMBER IS BEGIN RETURN p_dt1 - p_dt2; END; It's not obvious, though, what benefit you derive from doing this rather than simply. Query all. This is from my own library, will return the difference of months between two dates. Any help would be appreciated. Share. 25)) AS `numberofemployees`. That prevents. 2. A number representing the input date between January 1, 1970 and Dec 31, 2037. Date2Date. Improve this answer. inner select select DATEDIFF(MONTH, 0, GETDATE()) will give the number of months from 1900-01-01 here it is 1350. The function INTCK ('MONTH','1feb1991'd,'31jan1991'd) returns –1 because the first date is in a later discrete interval than the second date. The DATEDIFF function does not calculate the difference in months based on days. I am looking for solution how to select number of days between two dates without weekends and public holidays. I say ALL months as months can have 28 days (29 in a leap year), 30 days and 31 days which is why I wouldn't simply calculate the days between two dates. If date1 is earlier than date2 , then the result is negative. 0. Another example is to get the month of. Multiply it by seven to give the number of weeks spanned. SELECT date_part ('month',age ('2016-06-30', '2018-06-30')) The result of this query is 0. SELECT floor ( months_between ( date_1, date_2 )/12) floor_years_between FROM employee. The following example illustrates how to use the. . PostgreSQL. 1. See the following conditions: If date1 is later than date2, then the result is positive. DateGroup. This function helps to retrieve any particular value of the timestamp in any format that we wish. 0. The part to return. ) Description It's easy to do date arithmetic in Oracle Database, but it can be hard to remember the formulas. And determining if the date falls on a holiday (by querying against your holiday table) should be trivial. MONTHS_BETWEEN returns number of months between dates date1 and date2. So given Netezza is based on PostgreSQL, so it's AGE function, is equivalent to Snowflake's DATEDIFF, but like PostgreSQL interval it defaults to expressing it in simplified terms of Years/Months/Days. Admission_Date) > 5. End date will be sysdate. The MDX DateDiff function for Essbase returns the difference (a number) between two input dates in terms of the specified date-parts, following a standard Gregorian calendar. 25) This seems to be another common approach - and was also given in a comment on my question. 2425. 3. 2903225806 DATE_DIFF =. date_to) - (DATEDIFF(WK, evnt. For example, this function returns 1. The easiest is the connect by level method: Copy code snippet. You can include Oracle hints in PeopleSoft Query expressions as long as you adhere to the following rules: Expressions containing a hint must begin with /*+ . The format argument is a string format that specifies which unit the date should be rounded to. This is in the manual. Just divide the total by 7 to get the weeks and then calculate the remaining days. where (year(getdate())-year(birthDate)) = 17. For example, we can use the DATEPART function to get the day of a given date to determine whether an order was placed on Sunday or not. SELECT DATEADD (month, 1, '20220730'); The below DATEADD will add 1 year to the provided date value, the year changed from 2022 to 2023. date_from, evnt. See Date and Time Data Types and Functions (Transact-SQL) for an overview of all Transact. Do this even for a single day—e. Table 9. Start date will. This works as Oracle will perform an implicit cast (using TO_TIMESTAMP( time, format_mask )) using the session parameter. If the year diff has to be counted this way then use: EXTRACT (YEAR FROM date_to) - EXTRACT (YEAR FROM date_from) Just for the log. Access Function: DateDiff ("m",PAID_DATE,STATIC_DATE) AS Months_Between. MONTH_START_DATE > DATEADD (MONTH, -1, h. Date 1: 10th March 2011. Calculate the last date of the month is quite simple calculation -. 2 Answers Sorted by: 0 The best thing to do in this case is to use Oracle's MONTHS_BETWEEN () function. 15 between 2 values that are 1 year, 1 month and 15 days apart. Examples of Results in Months. DATEADD (date part, units, date or datetime) Return date math results: datetime DATEDIFF (date part, start date, end date) Give the difference between 2 dates in units specified by. Oracle's MONTHS_BETWEEN on the other hand tries to calculate an exact difference in months' fractions: select months_between(date '2021-02-01', date '2021-01-31') from dual; => 0. Java date functions. Viewed 417k times 57 I would. v_interval := p_end_date - p_start_date + 1; -- calculate total number of days between dates, including start and end dates. Write queries for continuous periods as explicit range condition. In Oracle SQL, I want to display the difference between two dates in the format 'x years y months z days'. The screenshot below shows the data I want as well as the incorrect month between results I am obtaining. Here is some T-SQL that gives you the number of years, months, and days since the day specified in @date. BI Publisher has extended a set of SQL and XSL functions for use in RTF templates. This works, but it is a bit clumsy compared to the sql server function:So, the weird number you see is the difference between the two dates. DateDiff: 2つの日付間の間隔数を戻します。 DatePart: DatePart(inverval,date[,firstdayofweek[,firstweekofyear]]) DateSerial: DateSerial(year,month,day) Day: 月の日(1から31まで)を表す数字を戻します。 Hour: 日の時間(0から23まで)を表す数字を戻します: IsDateThe easiest solution (ignoring leap years and whatnot) is to use DATEDIFF. 1. The system calculates the number of complete months between given dates. DATEDIFF(month, 0, GETDATE()) will give you the number of months from 1900-01-01 until now. I am running a simple DATEDIFF query but it doesn't seem to calculate the days properly or i'm doing something wrong. Viewed 4k times 1 I have a table with below structure. this will gives you the last 3 month date (from 1st of the month) WHERE date_column >= DATEADD (MONTH, DATEDIFF (MONTH, 0, GETDATE ()) - 3, 0) you have 3 date. ADD_MONTHS. INTERVAL '15. DATE_DIFF = 1. Examples of Results in Months. ( See. g. select *, cast ( (cast (begin_date as date) - cast (end_date as date) YEAR) as decimal (3,2)) AS year_diff from x. The syntax for these extended functions is. 999 is to not use the between comparison and instead use column_name >= @StartDate and column_name < @EndDate +1. event_id, evnt. CREATE OR REPLACE FUNCTION datediff (p_what IN VARCHAR2, p_d1 IN DATE, p_d2 IN DATE) RETURN NUMBER /* Updated to reflect current database and PL/SQL. The days are in two different, adjacent months, so the answer is 1 month difference. Select(x => x. (Oct 2006 - June 2005 = 16) DP_WEEK returns the distance between the weeks capturing the input dates. To make it easier for now, business day is simply weekdays and does not consider public holiday. When the reporting date month is the same as the target month you can get a round up To get the number of month or day, you change the first argument to month or day as shown below: Notice that the DATEDIFF () function takes the leap year into account. 99. . The SQL code is "where fac. Oracle equivalent to SQL Server/Sybase DateDiff. In addition, with DATEDIFF () the column is an argument to the function. 850". select (sysdate +1 - rownum) dt from dual connect by rownum <= (sysdate - add_months (sysdate - extract (day from sysdate),-2)); The "-2" is the number of prior full months of dates to include. select emplid from. That prevents. @WernfriedDomscheit YYYY-MM-DD is not a date it is just a formatted string. DATEDIFF(interval, date1, date2) Parameter Values. The first one involves getting the difference in days and then converting it to 'x year y month z days'. , YEAR, MONTH, DAY,. 1. The second method uses an extract function to obtain the years, months, and days separately. mm is a two digits of minute (00 through 59). mysql> SELECT something FROM tbl_name-> WHERE DATE_SUB(CURDATE(),INTERVAL 30 DAY) <= date_col; The query also selects rows with dates that lie in the future. NEXT_DAY: Returns a datetime value that represents the first weekday, named by string-expression, that is later than the date inexpression. If you want to confirm, simply run this. The return type is always DATE, regardless of the datatype of date. PRINT DATEDIFF(Day, 2010-02-20, 2010-01-01) RETURN 20SELECT DATEDIFF (MM,0,GETDATE ()) Add same number of month to date 0 (1901/01/01) SELECT DATEADD (MM, DATEDIFF (MM,0,GETDATE ()),0) Then we will get first day of current month (Current Date or a given date) To get Last Day of Last Month. The following example returns a difference in months between two dates: July 01 2017 and January 01 2017: SELECT MONTHS_BETWEEN( DATE '2017-07-01', DATE '2017-01-01') MONTH_DIFF FROM DUAL; Code language: SQL (Structured Query Language) (sql) The result is 6 months as shown below: with cte (start_date, end_date) as ( select date '2020-10-01', date '2020-11-02' from dual ), rcte (start_date, end_date, part_month) as ( select start_date, end_date, trunc(start_date, 'MM') from cte union all select start_date, end_date, part_month + interval '1' month from rcte where part_month < trunc(end_date, 'MM') ) select extract(month. I tried going off of something like this: Select records from SQL Server if greater than 6 months but I get the error: Subquery returned more than 1 value. Tdy. I want to calculate the current Age from Date of Birth in my Oracle function. startdate: The first date or datetime value. Return the current time. Asked 1 year, 8 months ago. StartTime: 2022-27-27 14:00:00 EndTime:2022-12-12 19:30:00 Firstly, to find the time difference, we will use. Consider SQL Server function to calculate the difference between 2 dates in months: SQL Server : -- Difference between Oct 02, 2011 and Jan 01, 2012 in months SELECT DATEDIFF ( month, '2011-10-02', '2012-01-01') ; -- Result: 3. ADD_MONTHS. for example Feb-15th to Mar-15th is a month. If the endDate has a day part less than startDate, it will get pushed to the previous month, thus datediff will give the correct number of months. Calculate difference between 2 date / times in Oracle SQL. If you need to calculate minutes or seconds, you simply multiply the result by a constant: (date2 - date1)*1440 -- number of minutes (date2 - date1)*86400 -- number of seconds. day: Number - The day of the month (1-31). DiffMonths Returns the difference in months between two dates. Get Number of Months Between 2 Dates. It counts the number of year boundaries between two dates. The Days, Months, and Years parameters can be negative or positive. SELECT DATEADD (month, 1, '20220730'); The below DATEADD will add 1 year to the provided date value, the year changed from 2022 to 2023. SELECT DATEDIFF (MONTH, '1/1/2014', '12/31/2014') and SELECT DATEDIFF (MONTH, '1/1/2014', '12/30/2014') both return 11. Firstly, for example, it doesn’t really hold a date, instead it records a datetime. Month difference between two dates in sql server. 1. It takes into account the fact that DATEDIFF() computes the difference without considering what month or day it is (so the month diff between 8/31 and 9/1 is 1 month) and handles that with a case statement that decrements the result. 679 seconds. This page provides you with the most commonly used Oracle date functions that help you handle date and time data easily and more effectively. g. To retrieve this number, use any of the following functions: Today (), TodateEx (), GetFirstDate (), GetLastDate (), DateRoll (). ToDate)); My SQL to LINQ Recipe might help you with some translation issues in the future. In Oracle, MONTHS_BETWEEN(date1, date2) function returns the number of months between two dates as a decimal number. 14. Share. [proc_datediff] ( @date datetime ) as begin DECLARE @diff varchar(70) DECLARE @tmpdate datetime, @years int, @months int, @days int SELECT @tmpdate = @date SELECT @years =. Then, it converts that result to a date, using the format 'yyyy-MM-dd'. 1 Answer. In this article, we learned how to do SQL subtract dates using the DATEDIFF function. Viewed 43k times 0 I want to. If you also need the additional months old, and days old. There are many tricks to generate rows in Oracle Database. The desired output is: CustName Year OrderDate AA 2000 01-JAN-2000 AA 2000 05-FEB-2000 AA 2000 10-MAR-2000 AA 2007 05-MAY-2007 AA 2007 07-JUN-2007 AA 2007 06-JUL-2007. g. We will use the below date for the examples. The months_between function returns the elapsed months going from the second date to the first. COMPUTE days2 = DATEDIFF(date2,date1,"days"). In my opinion the date diff is kind of subjective, especially on days. So it's not an accumulative difference, it's only when a date is within a smaller month. E. The number is the number of seconds elapsed since midnight, January 1, 1970. 一重引用符で囲んだ'YYYY-MM-DD[*HH:MI[:SS]]'形式の文字列(*はコロン(:)または空白でも可)、または現在の日付を返す引用符なしの@DATENOW. maybe something like passing an "m" as one of the parameters. In addition, with DATEDIFF () the column is an argument to the function. Now for testing purposes I need to compare the data for the last say 4 months from the sysdate. 2. DATEDIFF() Returns the difference between the two dates. And then we need to convert the output of DATEPART to a 2-digit month number. The date calculator calculates the difference between the 'Start Date' and 'End Date' and displays it in terms of the number of years, months, weeks and days between them. SELECT DATEADD ( quarter, DATEDIFF. Return the months between dates Find the difference between datetimes in years down to seconds Define default formatting for datetime data types Cheat sheet. select DATEADD(MONTH,1350,0) will give 2012-07-01 00:00:00. Oracle's MONTHS_BETWEEN on the other hand tries to calculate an exact difference in months' fractions: select months_between(date '2021-02-01', date '2021-01-31') from dual; => 0. Result: 505 rows listed. SUBDATE (`Date`,WEEKDAY (`Date`)-1) This is the simplest version and returns the full date of the Sunday for the given week. There are two methods to achieve this. Push out all due dates by one week. 00. The function INTCK ('MONTH','31jan1991'd,'1feb1991’d) returns 1, because the two dates lie in different months that are one month apart. Then it subtracts a year if the birthdate hasn't passed. ops$tkyte@8i> select months_between ( end_date, start_date ), 2 trunc ( months_between ( end_date, start_date ) /12 ) Years, 3 mod (. dividing by 365. DATE_FORMAT () Format date as specified. I have a table where PurchasedDate is maintained. The next example will show the differences between two dates for each specific datapart and abbreviation. This function is not sensitive to the NLS_CALENDAR session parameter. The system calculates the number of complete months between given dates. Please refer the below examples and kindly let me know your ideas. Sorted by: 3. 0 and later Information in this document applies to any platform. 0- 64bit Production With the Partitioning and Data Mining options'. 1970年1月1日から2037年12月31日までの入力日付を示す数値。. select distinct e1. Modified 3 months ago. SELECT SYSDATE AS "Date" FROM DUAL; SYSDATE returns the system date and time but does not display the time unless formatted to do so with the function TO_CHAR (): SELECT TO_CHAR (SYSDATE,. - Find the “date_diff” in minutes and add it with the “date_diff” in hours and the “date_ diff” in days. This function adds a specified number of days, months, and years to a given date. The DATEPART() function returns an integer which is a part of a date such as a day, month, and year. 指定した日付の差異。次の値が有効です。 DD: 差異を日数で計算します。. Hi team i need to get the exact month differences between two dates i am using oracle sql for my project . Beneath the plainness of its name, it hides a little depth. The difference between two dates (in oracle's usual database product) is in days (which can have fractional parts). Which leads me to believe that it is treating February. The DATEDIFF() function returns the difference between two dates. For example, you might use DateDiff to calculate the number of days between two dates, or the number of weeks between today and the end of the year. 5 = 0. datediff (q,start date,end date) i. So far I have this: SELECT evnt. lastModified - w. The next example will show the differences between two dates for each specific datapart and abbreviation. 3. 15 minutes. DATEDIFF with examples DATEDIFF function accepts 3 parameters, first is datepart (can be an year, quarter, month, day, hour etc. 3 Answers. – user330315. This conversion uses the NLS_DATE_FORMAT parameter to decide the format of the output string. If date1 is earlier than date2, then the result is negative. select datediff (q,'03-30-2005','04-01-2005') will return 1. DateDiff(“m”, Fields! starting date. QlikView date and time functions are used to transform and convert date and time values. Viewed 110k times 49 I have a table with following structure. Answer: Oracle supports date arithmetic and you can make expressions like "date1 - date2" using date subtraction to get the difference between the two dates. Oracle SQL - CASE in a WHERE clause. Hi Ive been having an issue with getting the correct difference in a date from the current month not including the day. date_to, DATEDIFF(DD, evnt. DATE_DIFF. sql-server. Another solution by using Cross Apply:. Just to clarify SQL server seems to require DATEDIFF (datepart, recentDate, olderDate) as startdate and enddate are a bit nebulous. (year/month/date from date) //oracle function for extracting values from date. select level rn from dual connect by level <= 3; RN 1 2 3. For example, assume that you had two elements, FIRST_NAME and LAST_NAME to concatenate into a 30-character field. In this, we will add the number of years that we expect this person to turn in a given year, based on the DATEDIFF( ) results. Just divide the total by 7 to get the weeks and then calculate the remaining days. Fractions are allowed; you can add 2. The datepart value cannot be specified in a variable, nor as a quoted string like 'month'. We will be using the same employees table in order to demonstrate the intricacies of calculating the difference between two dates in terms of weeks, months, or years using MySQL’s DATEDIFF() function. Share. I apologize for the misinformation. Oracle's database does not have (nor need) a datediff() function. You can write the query in a SQL statement using the DATEADD and DATEDIFF() function. DATEDIFF (MONTH, DATEADD (DAY,-DAY (startDate)+1,startDate),DATEADD (DAY,-DAY (startDate)+1,endDate)) Share. Should I change (edit) the title or delete and re-post the question properly? This is what I'm addressing. However, The problem is different number of records because DATEDIFF(month,a,b)<=4 in SQL Server returns only the month difference whereas months_between(a,b)<=4 in oracle returns the. v_modweek := mod ( v_interval, 7); -- calculate how many days remain after computing the total number of. Note that SQL Server DATEDIFF(month, date2, date1) function does not return exactly the same result, and you have to use an user-defined function if you need to fully emulate the Oracle MONTHS_BETWEEN function (see. Example Getting the months and years between two dates using Datediff There is a round up issue with the Datediff function. Start date will be equal to add_months(sysdate,-6) And . HQL And datediff() Functions. Also, since you mentioned SAS, here is the SAS syntax to do the same thing: WHERE d_date > intnx ('MONTH', today (), -6, 'SAME');Query Manager inserts the expression into the SQL for you. Then it calculates the number of months that have passed until your given date (@test) by fours steps: 1. In certain cases, such as string-based comparisons or when a result depends on a different timestamp format than is set in the session parameters, we recommend explicitly converting. (You can also subtract fractions of days, but that might be outside the scope of this answer. SELECT floor ( months_between ( date_1, date_2 )/12) floor_years_between FROM employee. ADD_MONTHS returns slightly different results than DATEADD used with a MONTH component:. And what date you want to get for example difference between dates 456 days it's mean: 1 year 3 month and several days. g. here i am trying get the month differences between two. startdate)-1 as [Datediff] from #temp e1 join #temp e3. In PostgreSQL there are basically 2 functions to do the same, as we have both date_part and extract: SELECT current_date AS ACTUAL_DATE, EXTRACT (DAY FROM current_date) AS ACTUAL_DAY, EXTRACT (MONTH FROM current_date) AS ACTUAL_MONTH, EXTRACT (YEAR FROM current_date) AS ACTUAL_YEAR. current_timestamp() returns the timestamp on the database client side. ROUND returns date rounded to the unit specified by the format model fmt. you can check against last 90 days. DATEDIFF with examples DATEDIFF function accepts 3 parameters, first is datepart (can be an year, quarter, month, day, hour etc. The following shows the syntax of the DATEPART() function: DATEPART ( date_part , input_date ) Code language: SQL (Structured Query Language) (sql) The DATEPART() takes two arguments: date_part is the part of a date to be extracted. Month([EndDate]) - DateMonth([StartDate]) Regards, Pat29 Answers. Click on the function name to jump to a discussion of that function. DAYS(date2 - date1). Example. 032258 the problem lies in the fact that a month is a nebulous thing - it is not a precise number of days. see this sqlfiddle. Oracle DATEDIFF函数在Oracle中的使用 在本文中，我们将介绍Oracle数据库中的DATEDIFF函数。 阅读更多：Oracle 教程 什么是DATEDIFF函数？ DATEDIFF函数用于计算两个日期之间的时间间隔。它可以在Oracle数据库中使用，并返回一个整数值，表示两个日期之间的差异。这对于计算两个日期之间的天数、小时数、分钟. 利用日期间的加减运算. for oracle: months_between. Improve this answer.